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How to solve perimeter based problems for class 8 maths
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Jun 10, 2025
How to solve perimeter based problems for class 8 maths
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0:00
welcome students this video is about
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menation problems for class 8 question
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number one an ant is moving around a few
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food pieces of different shapes
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scattered on the floor for which food
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piece would the ant have to take a
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longer round remember circumference of
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the circle can be obtained by using the
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expression C= 2 pi R where R is the
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radius of the circle in these type of
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problems we need to count the length of
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the shape so we need to look at the
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parameter of the shape so now take a
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look at the parameter of the shape for
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the first case the parameter of shape
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would consist of parameter of
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semicircular part and diameter of the
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part so parameter of semicircular part
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is given by p r and diameter is
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given by 2 r where r is the radius of
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the circle so substituting the values of
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pi and r here we get perimeter of the
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first shape as 7.2 cm in the second case
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the parameter of shape consist of three
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things first the parimeter of
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semic-ircular parts then we have two
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length side here and then one bread side
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so again substituting the value of those
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uh length breadth and radius we get
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p r + 12 + b that is equal to 4.4 +
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3 + 2.8 that is equal to 10.2 cm now
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let's take a look at the third part the
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parameter of the third shape consist of
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parameter of the semicircular part plus
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two slant heights so substituting those
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values 4.4 + 4 is equal to 8.4 cm so
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from the three numerical values we can
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see that first shape the ant would have
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to cover least distance and in the
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second shape ant has to travel the
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longest distance for more notes and
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study material please visit our website
1:50
physicscatalyst.com
#Primary & Secondary Schooling (K-12)